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Creating an image gallery without MySQL
Publishing date: 15-04-2011 -
Copyright © Claudiu Gilcescu-Ceia
Ever wanted to create a photo gallery that would fetch the photos from a folder on the server without actually taking the image paths from a database?
Well, here's a small code snippet that would solve the problem for you and output the paths to the images into an XML with the following structure:
CODE:
<?xml version="1.0" encoding="utf-8"?>
<gallery>
<item iPath="path/to/file1.jpg"/>
<item iPath="path/to/file2.jpg"/>
</gallery> If you have any questions regarding it, or encounter any issues implementing it in your own project, drop a comment, I'll help you as I can.
CODE:
<?php
header("content-type:text/xml;charset=utf-8");
function getDirTree($dir,$p=true) {
if (!is_dir($dir)) return false;
$d = dir($dir);
$x=array();
while (false !== ($r = $d->read())) {
if($r != "." && $r != ".." && (($p == false && is_dir($dir.$r)) || $p == true)) {
$x[$r] = (is_dir($dir.$r) ? array() : (is_file($dir.$r) ? true : false));
}
}
foreach ($x as $key => $value) {
if (is_dir($dir.$key."/")) {
$x[$key] = getDirTree($dir.$key."/", $p);
}
}
ksort($x);
return $x;
}
function parse($dir) {
$tree = getDirTree($dir, true);
if ($tree) {
foreach ($tree as $k=>$v) {
if (is_array($v)) {
foreach ($v as $key=>$val) {
if (!is_array($key)) {
if (substr($key,-4)==='.jpg') {
echo '<item iPath="'.$key.'"/>';
}
else {
if (is_array($val)) {
parse($dir.$k."/");
}
}
}
}
}
}
}
return false;
}
echo '<?xml version="1.0" encoding="utf-8"?>
<gallery>';
parse('repository/');
echo '</gallery>';
?> The code might still contain some "artifacts" from tests and such, please delete them if you spot them, the code works regardless so don't worry.
The code in this article is distributed under the MIT license 
You can visit the author's website at blog.hazardousgaming.info
Publishing date: 15-04-2011 -
Copyright © Claudiu Gilcescu-Ceia
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